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Solution of Soil Compaction Check Via The Voids Ratio

Articles > Solution of Soil Compaction Check Via The Voids Ratio

Question:

A contractor has compacted the base course for a new road and found that the mean value of the test samples shows w = 14.6%, Gs = 2.81, and γ = 18.2 kN/m3. The specifications require that e < 0.80. Has the contractor complied with the specifications?

 

Solution:

For formulas of soil phase relationships read Soil Phase Relationships article.

gamma = frac{G_s gamma_w (1+w)}{1+e}

Thus

1+e = frac{G_s gamma_w (1+w)}{gamma}

1+e = frac{2.81 (9.81) (1+0.146)}{18.2}=1.74

e =1.74-1=0.74leq0.8

Yes, the contractor has complied.


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