# Solution of Soil Compaction Check Via The Voids Ratio

Articles > Solution of Soil Compaction Check Via The Voids Ratio

### Question:

A contractor has compacted the base course for a new road and found that the mean value of the test samples shows w = 14.6%, Gs = 2.81, and γ = 18.2 kN/m3. The specifications require that e < 0.80. Has the contractor complied with the specifications?

### Solution:

For formulas of soil phase relationships read Soil Phase Relationships article.

$\gamma = \frac{G_s \gamma_w (1+w)}{1+e}$

Thus

$1+e = \frac{G_s \gamma_w (1+w)}{\gamma}$

$1+e = \frac{2.81 (9.81) (1+0.146)}{18.2}=1.74$

$e =1.74-1=0.74\leq0.8$

Yes, the contractor has complied.