# Solved Example: Analysis of a one-way spanning unreinforced masonry wall panel (BS 5628)

**Articles > Solved Example: Analysis of a one-way spanning unreinforced masonry wall panel (BS 5628)**

### Question:

Estimate the characteristic wind pressure that the cladding panel shown below can resist assuming that it is constructed using bricks having a water absorption of < 7% and mortar designation (iii). Assume γf = 1.2 and γ_{m} = 3.0.

### Solution:

ULTIMATE DESIGN MOMENT (M)

Since the vertical edges are unsupported, the panel must span vertically and, therefore, following equations

cannot be used to determine the design moment here. The critical plane of bending will be parallel to the bed joint and the ultimate design moment at mid-height of the panel, M, is given by (clause 32.4.2 of BS 5628)

Ultimate load on the panel = wind pressure * are

Hence

MOMENT OF RESISTANCE (M_{d})

Section modulus (Z):

Moment of resistance:

The design moment of resistance, M_{d}, is equal to the moment of resistance when the plane of bending is parallel to the bed joint, M_{k par}. Hence

where f_{kx par} = 0.5 N mm−2 from table below (Table 3 BS 5628), since water absorption of bricks < 7% and the mortar is designation (iii).

DETERMINATION OF CHARACTERISTIC WIND PRESSURE (W_{k})

For structural stability:

Hence the characteristic wind pressure that the panel can resist is 0.216 × 10^{−3} N mm^{−2} or 0.216 kN m^{−2}.

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